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Let G be a group, N a normal subgroup of G and H a subgroup of G. The following statements are equivalent:
If one (and therefore all) of these statements hold, we say that G is a semidirect product of N and H, or that G splits over N, and we write G = N⋊H.
If G is the semidirect product of the normal subgroup N and the subgroup H, and both N and H are finite, then the order of G equals the product of the orders of N and H.
Note that, as opposed to the case with the direct product, a semidirect product is not, in general, unique; if G and G' are two groups which both contain N as a normal subgroup and H as a subgroup, and both are a semidirect product of N and H, then it does not follow that G and G' are isomorphic.
If G is a semidirect product of N and H, then the map φ : H → Aut(N) (where Aut(N) denotes the group of all automorphisms of N) defined by φ(h)(n) = hnh-1 for all h in H and n in N is a group homomorphism. It turns out that N, H and φ together determine G up to isomorphism, as we will show next.
Given any two groups N and H (not necessarily subgroups of a given group) and a group homomorphism φ : H → Aut(N) , we define a new group N ⋊φH, the semidirect product of N and H with respect to φ as follows: the underlying set is the cartesian product N × H, and the group operation * is given by
for all n1, n2 in N and h1, h2 in H. This defines indeed a group; its identity element is (eN, eH) and the inverse of the element (n, h) is (φ(h-1)(n-1), h-1). N × {eH} is a normal subgroup isomorphic to N, {eN} × H is a subgroup isomorphic to H, and the group is a semidirect product of those two subgroups in the sense given above.
Suppose now conversely that we are given an internal semidirect product as defined above, i.e. a group G with a normal subgroup N, a subgroup H, and such that every element g of G may be written uniquely in the form g=nh where n lies in N and h lies in H. Let φ : H→Aut(N) be the homomorphism
Then G is isomorphic to the outer semidirect product NφH; the isomorphism sends the product nh to the tuple (n,h). In G, we have the rule
and this is the deeper reason for the above definition of the outer semidirect product, and an easy way to memorize it.
A version of the splitting lemma for groups states that a group G is isomorphic to a semidirect product of the two groups N and H if and only if there exists a short exact sequence
and a group homomorphism r : H → G such that v o r = idH, the identity map on H. In this case, φ : H → Aut(N) is given by