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Home > Quadratic equation


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In mathematics, a quadratic equation is a polynomial equation of the second degree. The generalized form is

The numbers a, b and c are called coefficients: a is the coefficient of x2, b is the coefficient of x, and c is the free term or constant.

Take, for example, 5x2 + 3x + 4 = 0. In this example, 5 is the coefficient of , 3 is the coefficient of x, and 4 is the free term.

A quadratic equation with real or complex coefficients has two complex roots (i.e., solutions) usually denoted as and , although the two roots may be equal. These roots can be computed using the quadratic formula.

Higher order equations may be quadratic in form, such as:

.

Note that the highest exponent is twice the value of the exponent of the middle term. This equation may be resolved directly or with a simple substitution, using the methods that are available for the quadratic, such as factoring (also called factorising), the quadratic formula, or completing the square.

1 Quadratic formula

The quadratic formula explicitly gives the solutions of a quadratic equation in terms of the coefficients a, b and c, which we temporarily assume to be real (but see below for generalizations) with a being non-zero. These solutions are also called the roots of the equation. The formula reads

An alternate form sometimes encountered is given by

The term b2 − 4ac is called the discriminant of the quadratic equation, because it discriminates between three qualitatively different cases:

Note that when computing roots numerically, the usual form of the quadratic formula is not ideal. See Loss of significance for details.

2 Derivation

The quadratic formula is derived by the method of completing the square.

Dividing our quadratic equation by a, we have

which is equivalent to

The equation is now in a form in which we can conveniently complete the square. To "complete the square" is to add a constant (i.e., in this case, a quantity that does not depend on x) to the expression to the left of "=", that will make it a perfect square trinomial of the form x2 + 2xy + y2. Since "2xy" in this case is (b/a)x, we must have y = b/(2a), so we add the square of b/(2a) to both sides, getting

The left side is now a perfect square; it is the square of (x + b/(2a)). The right side can be written as a single fraction; the common denominator is 4a2. We get

Taking square roots of both sides yields

Subtracting b/(2a) from both sides, we get



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