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If F and G are functors between the categories C and D, then a natural transformation η from F to G associates to every object X in C a morphism ηX : F(X) → G(X) in D, such that for every morphism f : X → Y in C we have ηY O F(f) = G(f) O ηX. This equation can conveniently be expressed by the commutative diagram
If one or both of F or G are contravariant the corresponding horizontal arrow is reversed. If η is a natural transformation from F to G, we also write η : F → G. This is also expressed by saying the family of morphisms ηX : F(X) → G(X) is natural in X.
If, for every object X in C, the morphism ηX is an isomorphism in D, then η is said to be a natural isomorphism (or sometimes natural equivalence or isomorphism of functors). Two functors F and G are called naturally isomorphic or simply isomorphic if there exists a natural isomorphism from F to G.
Statements like
abound in modern mathematics. We will now give the precise meaning of this statement as well as its proof. Consider the category Grp of all groups with group homomorphisms as morphisms. If (G,*) is a group, we define its opposite group (Gop,*op) as follows: Gop is the same set as G, and the operation *op is defined by a*opb = b*a. All multiplications in Gop are thus "turned around". Forming the opposite group becomes a (covariant!) functor from Grp to Grp if we define fop = f for any group homomorphism f: G → H. Note that fop is indeed a group homomorphism from Gop to Hop:
The content of the above statement is:
To prove this, we need to provide isomorphisms ηG : G → Gop for every group G, such that the above diagram commutes. Set ηG(a) = a-1. The formulas (ab)-1 = b-1 a-1 and (a-1)-1 = a show that ηG is a group homomorphism which is its own inverse. To prove the naturality, we start with a group homomorphism f : G → H and show ηH o f = fop o ηG, i.e. (f(a))-1 = fop(a-1) for all a in G. This is true since fop = f and every group homomorphism has the property (f(a))-1 = f(a-1).