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The Monty Hall problem is a puzzle in probability that is loosely based on the American game show Let's Make a Deal; the name comes from the show's host Monty Hall. In this puzzle a contestant is shown three closed doors; behind one is a car, and behind each of the other two is a goat. The contestant is allowed to open one door, and will win whatever is behind the door he opens; however, after the contestant has selected a door but before he actually opens it, the host (who knows what is behind each door) opens one of the other doors to show that there is a goat behind it, and asks the contestant whether they want to change their mind and switch to the other closed door. Does the contestant improve their chance of winning the car by switching or does it make no difference?

The question has generated heated debate. As the solution appears to contradict elementary ideas of probability and common sense, it may be regarded as a paradox.

1 Problem and solution

1.1 The problem

Here is a famous statement of the problem, from a letter from Craig F. Whitaker to Marilyn vos Savant's column in Parade Magazine in 1990 (as quoted by Bohl, Liberatore, and Nydick).

Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?

This is a restatement of the problem as given by Steve Selvin in a letter to the American Statistician (February, 1975). As stated, the problem is an extrapolation from the game show: contestants on Let's Make a Deal were not allowed to switch. As Monty Hall wrote to Selvin [1],

And if you ever get on my show, the rules hold fast for you -- no trading boxes after the selection.

Selvin's subsequent letter to the American Statistician (August, 1975) appears to be the first use of the term "Monty Hall problem".

An essentially identical problem appeared as the "three prisoners problem" in Martin Gardner's Mathematical Games column in 1959. Gardner's version makes the selection procedure explicit, avoiding the unstated assumptions in the version given here.

1.2 The solution

The solution to the problem is yes: the chance of winning the car is doubled when the contestant switches to another door rather than sticking with the original choice. When the contestant chooses a door, there is a probability of 1/3 that they choose the door with the car: there is a probability of 2/3 that they do not choose the door with the car. When the host opens a door to reveal a goat, there is still a probability of 2/3 that the contestant has not chosen the door with the car (because when the host reveals a goat it does not affect this probability). Therefore if the contestant switches their choice, there is now a probability of 2/3 that they have chosen the door with the car.

2 Aids to understanding




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