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The general formula for halogenoalkanes is CnH2n+1X (where X is the halogen). Thus, an example of a structural formula is, for bromoethane, CH3CH2Br. As is noted, the naming convention involves the halogen as a prefix to the alkane. This is why ethane with bromine becomes bromoethane; as butane with chlorine becomes chlorobutane.
Halogenoalkanes can be synthesized from alkanes, alkenes, or alcohols.
Alkanes react with halogens by free radical halogenation. In this reaction a hydrogen atom is removed from the alkane, then replaced by a halogen atom by reaction with a diatomic halogen molecule. Thus:
Step 1. X2 → 2 X. (Initiation Step)
Step 2. X. + R-H → R. + HX (1st Propagation Step)
Step 3. R. + X2 → R-X + X. (2nd Propagation Step)
Steps 2 and 3 keep repeating, each providing the reactive intermediate needed for the other step. This is called a radical chain reaction.
An alkene reacts with a hydrohalic acid (HX) to form an alkyl halide. The double bond of the alkene is replaced by two new bonds, one to the halogen and one to the hydrogen atom of the hydrohalic acid. Markovnikov's rule states that in this reaction, the halogen becomes attached to the more substituted carbon. Example:
CH3-CH=CH2 + HBr → CH3-CHBr-CH3 (not CH3-CH2-CH2Br).
Alkenes also react with halogens to form halogenoalkanes with two neighboring halogen atoms. This is sometimes known as "decolorizing" the halogen since the reagent X2 is colored and the product is usually colorless. Example:
CH3-CH=CH2 + Br2 → CH3-CHBr-CH2Br
Certain reagents such as SOCl2 (thionyl chloride) can be used to convert alcohols to alkyl halides.