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Exact constant expressions for trigonometric expressions are sometimes useful, mainly for simplifying solutions into radical forms which allow further simplification.All values of sine, cosine, and tangent of angles with 3° increments are derivable using identities: Half-angle, Double-angle, Addition/subtraction and values for 0°, 30°, 36° and 45°. Note that 1° = π/180 radians.
1 Table of constants
Values outside 0° ... 45° angle range are trivially extracted from circle axis reflection symmetry from these values.
1.1 0° Fundamental
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1.2 3° - 60-sided polygon
- sin(3°) = [2√(5+√5)(1-√3)+√2(√5-1)(√3+1)]/16
- cos(3°) = [2√(5+√5)(1+√3)+√2(√5-1)(√3-1)]/16
- tan(3°) = [(2-√3)(3+√5)-2](2-√(2(5-√5)))/4
1.3 6° - 30-sided polygon
- sin(6°) = [√(6(5-√5))-(√5+1)]/8
- cos(6°) = [√(2(5-√5))+√3(√5-1)]/8
- tan(6°) = [√(5-2√5)(√5 + 1)+√3(1-√5)]/2
1.4 9° - 20-sided polygon
- sin(9°) = [-2√(5-√5)+√2(√5 + 1)]/8
- cos(9°) = [+2√(5-√5)+√2(√5 + 1)]/8
- tan(9°) = -√(5-2√5)(2+√5)+(√5 + 1)
1.5 12° - 15-sided polygon
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- tan(12°) = [√(5-2√5)(2+√5)+(√5+1)]/2
1.6 15° - 12-sided polygon
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1.7 18° - 10-sided polygon
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1.8 21° - Sum 9 + 12
- sin(21°) = [2√(5-√5)(√3+1)-√2(√3-1)(1+√5)]/16
- cos(21°) = [2√(5-√5)(√3-1)+√2(√3+1)(1+√5)]/16
- tan(21°) = [√(5-2√5)(1+2√3-√5)+(2+√3)(√5-3)+2]/2
1.9 22.5° - Octagon
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1.10 24° - Sum 12° + 12°
- sin(24°) = √(2(5+√5))(1-√5)+2√3(1+√5))/16
- cos(24°) = √(6(5+√5))(√5-1)+2(1+√5))/16
- tan(24°) = (√(10+2√5)-2√3)(3+√5)/4
- cotan(24°) = (√(10+2√5)+2√3)(√5-1)/4
1.11 27° - Sum 12° + 15°
- sin(27°) = ((2√(5+√5)+√2(1-√5))/8
- cos(27°) = ((2√(5+√5)+√2(√5-1))/8
- tan(27°) = -√(5-2(√5))+(√5-1)
1.12 30° - Hexagon
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1.13 33° - Sum 15° + 18°
- sin(33°) = (2√(5+√5)(-1+√3)+√2(√5-1)(1+√3))/16
- cos(33°) = (2√(5+√5)(+1+√3)+√2(√5-1)(1-√3))/16
- tan(33°) = (√(5(5-2√5))(-15+10√3-7√5+4√15)+5((-2+√3)(3+√5)+2))/10
1.14 36° - Pentagon
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1.15 39° - Sum 18°+ 21°
- sin(39°) = (2√(5-√5)(1-√3)+√2(+1+√3)(1+√5))/16
- cos(39°) = (2√(5-√5)(1+√3)+√2(-1+√3)(1+√5))/16
- tan(39°) = (√(2(5+√5))-2)((2-√3)(-3+√5)+2)/4
1.16 42° - Sum 21° + 21°
- sin(42°) = (√(6(5-√5))(1+√5)+2(1-√5))/16
- cos(42°) = (√(2(5-√5))(1+√5)+2√3(-1+√5))/16
- tan(42°) = (-√(5-2√5)(3+√5)+√3(1+√5))/2
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